Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - Chapter 4 Review Problem Set - Page 183: 12



Work Step by Step

Multiplying both sides by the $LCD= 3 $ and then using the properties of equality, the value of the variable that satisfies the given equation, $ \dfrac{2n-5}{3}=\dfrac{n+1}{3}+5 ,$ is \begin{array}{l}\require{cancel} 1(2n-5)=1(n+1)+3(5) \\\\ 2n-5=n+1+15 \\\\ 2n-n=1+15+5 \\\\ n=21 .\end{array}
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