## Elementary Algebra

He must shoot less than or equal to 77. The solution set is {x|x $\leq$ 77}.
Let x represent the score on the last day. The average for the five days is $\frac{82+84+78+79+x}{5}$. Because the average for the five days needs to be 80 or less, we solve the following inequality. $\frac{82+84+78+79+x}{5}$ $\leq$ 80 Multiply both sides by 5. 82+84+78+79+x $\leq$ 400 323 + x $\leq$ 400 x $\leq$ 77 He must shoot less than or equal to 77. The solution set is {x|x $\leq$ 77}.