Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - 4.5 - Inequalities, Compound Inequalities, and Problem Solving - Problem Set 4.5: 69

Answer

The largest possible value for the width of the rectangle is 15 inches.

Work Step by Step

Let w represent the width of the rectangle. The perimeter of the rectangle = width + width + length + length The perimeter of the rectangle = w + w + 20 + 20 The perimeter of the rectangle = 2w + 40 The perimeter should not be greater than 70, which means 2w + 40 $\leq$ 70. We solve this inequality to obtain: 2w + 40 $\leq$ 70 2w $\leq$ 30 Divide both sides by 2. w $\leq$ 15 The maximum value the width can be is 15.
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