## Elementary Algebra

Let x represent the score for the fourth exam, and y represent the score for the fifth exam. His average will be $\frac{96+90+94+x+y}{5}$. Because he must have an average higher than 92 for all five exams, we solve the following inequality. $\frac{96+90+94+x+y}{5}$ $\gt$ 92 Multiply both sides by 5. 96+90+94+x+y $\gt$ 460 280 + x + y $\gt$ 460 x + y $\gt$ 180 The sum of the last two exams must be greater than 180. To find their average, we divide the sum by 2. Their average is $\frac{x+y}{2}$. $\frac{x+y}{2}$ $\gt$ 90 So, their average needs to be greater than 90 for him to have an average higher than 92 for all five exams.