Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - 3.2 - Equations and Problem Solving - Problem Set 3.2 - Page 106: 46

Answer

C = $\frac{5}{9}$F - $\frac{160}{9}$

Work Step by Step

Using the properties of equality we obtain: $ F =\frac{9}{5}C + 32$ $ F - 32 = \frac{9}{5}C + 32 - 32$ Subtract 32 from both sides $ F - 32 = \frac{9}{5}C$ $F \times \frac{5}{9} - 32 \times \frac{5}{9} =\frac{9}{5}C \times \frac{5}{9}$ Muliply both sides by $\frac{5}{9}$ C = $\frac{5}{9}$F - $\frac{160}{9}$
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