Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - Chapter 2 Test - Page 90: 14


$= \frac{4y^{2}-5x}{xy^{2}}$

Work Step by Step

1) In order to find a common denominator, multiply the first fraction by $y^{2}/y^{2}$ and the second fraction by $x/x$ to obtain a common denominator of $xy^{2}$ 2) Subtract $= \frac{4}{x} - \frac{5}{y^{2}}$ $= \frac{4(y^{2})}{xy^{2}} - \frac{5(x)}{xy^{2}}$ $ = \frac{4y^{2}}{xy^{2}} - \frac{5x}{xy^{2}}$ $= \frac{4y^{2}-5x}{xy^{2}}$
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