Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - Chapter 2 Test - Page 90: 12


$= \frac{4y}{5}$

Work Step by Step

First, multiply the numerators and the denominators by each other. Next, cancel out common factors to obtain: $= \frac{8x}{15y} \times \frac{9y^{2}}{6x}$ $= \frac{72xy^{2}}{90xy}$ $= \frac{4y}{5}$
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