## Elementary Algebra

$= \frac{4y}{5}$
First, multiply the numerators and the denominators by each other. Next, cancel out common factors to obtain: $= \frac{8x}{15y} \times \frac{9y^{2}}{6x}$ $= \frac{72xy^{2}}{90xy}$ $= \frac{4y}{5}$