Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.5 - Translating from English to Algebra - Problem Set 2.5: 60

Answer

$P=6w+2$

Work Step by Step

Since the length is one more than $2$ times the width, $w$, we must multiply $w$ by $2$, and then add $1$ to find the length. This gives us a length of $2w+1$. The formula for the perimeter of a rectangle is $P=2l+2w$, where $l$ is the length and $w$ is the width. We plug in the values for width and length: $P=2(2w+1)+2(w)$ We apply the distributive property to expand the first term: $P=4w+2+2w$ We apply the commutative property of addition to rearrange the things being added: $P=4w+2w+2$ We add to combine like terms: $P=6w+2$
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