Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.2 - Addition and Subtraction of Rational Numbers - Problem Set 2.2: 87

Answer

$\frac{13}{20}n$

Work Step by Step

We first factor out $n$. Then, to simplify this expression, we find the common denominator (which is the LCM of the denominators of all of the fractions) to obtain: $\frac{3}{5}n-\frac{1}{4}n+\frac{3}{10}n$ =$n(\frac{3}{5}-\frac{1}{4}+\frac{3}{10})$ =$n(\frac{3(4)-1(5)+3(2)}{20})$ =$n(\frac{12-5+6}{20})$ =$n(\frac{7+6}{20})$ =$n(\frac{13}{20})$ =$\frac{13}{20}n$
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