## Elementary Algebra

Published by Cengage Learning

# Chapter 2 - Real Numbers - 2.2 - Addition and Subtraction of Rational Numbers - Problem Set 2.2 - Page 58: 87

#### Answer

$\frac{13}{20}n$

#### Work Step by Step

We first factor out $n$. Then, to simplify this expression, we find the common denominator (which is the LCM of the denominators of all of the fractions) to obtain: $\frac{3}{5}n-\frac{1}{4}n+\frac{3}{10}n$ =$n(\frac{3}{5}-\frac{1}{4}+\frac{3}{10})$ =$n(\frac{3(4)-1(5)+3(2)}{20})$ =$n(\frac{12-5+6}{20})$ =$n(\frac{7+6}{20})$ =$n(\frac{13}{20})$ =$\frac{13}{20}n$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.