## Elementary Algebra

Published by Cengage Learning

# Chapter 2 - Real Numbers - 2.2 - Addition and Subtraction of Rational Numbers - Problem Set 2.2 - Page 58: 60

#### Answer

$\frac{-65b-44a}{40ab}$

#### Work Step by Step

To simplify this expression, we first need to find the common denominator (the LCM), which is $40ab$. Therefore, we obtain: $-\frac{13}{8a}-\frac{11}{10b}$ =$\frac{-13(5b)-11(4a)}{40ab}$ =$\frac{-65b-44a}{40ab}$

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