Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.2 - Addition and Subtraction of Rational Numbers - Problem Set 2.2: 66

Answer

$\frac{5}{3}$

Work Step by Step

To simplify this expression, we first need to find the common denominator (the LCM) of every denominator, which is $12$. Therefore, we obtain: $\frac{3}{4}+\frac{2}{3}-\frac{1}{6}+\frac{5}{12}$ =$\frac{3(3)+2(4)-1(2)+5(1)}{12}$ =$\frac{9+8-2+5}{12}$ =$\frac{17+3}{12}$ =$\frac{20}{12}$ =$\frac{5}{3}$
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