## Elementary Algebra

$11-13i$
Multiplying each term of the first expression with the whole the second expression to simplify, we obtain: $(3+i)(2-5i)$ =$3(2-5i)+i(2-5i)$ =$6-15i+2i-5i^{2}$ =$6-15i+2i-5(-1)$ (as $i^{2}=-1$) =$6-15i+2i+5$ =$6+5-15i+2i$ =$11-13i$