Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - Chapter 11 Test - Page 521: 19



Work Step by Step

Using the rules of factoring trinomials, we obtain: $3x^{2}+5x-28=0$ $3x^{2}-7x+12x-28=0$ $x(3x-7)+4(3x-7)=0$ $(3x-7)(x+4)=0$ $(3x-7)=0$ and $(x+4)=0$ $x=\frac{7}{3}$ and $x=-4$ Therefore, the solution set is {$-4,\frac{7}{3}$}.
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