Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - Chapter 11 Test - Page 521: 10



Work Step by Step

Using the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$, we obtain: $\frac{30n^{\frac{1}{2}}}{6n^{\frac{2}{5}}}$ =$\frac{30}{6}\times\frac{n^{\frac{1}{2}}}{n^{\frac{2}{5}}}$ =$5\times n^{\frac{1}{2}-\frac{2}{5}}$ =$5\times n^{\frac{1(5)-2(2)}{10}}$ =$5\times n^{\frac{5-4}{10}}$ =$5\times n^{\frac{1}{10}}$ =$5n^{\frac{1}{10}}$
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