## Elementary Algebra

The temperature at noon is $-3˚F$
$= (-17) + 14$ $= 14 - 17$ $= -3˚F$ The initial temperature at 5 AM is $-17˚F$; this temperature increased by $14˚F$, which is a positive number. Therefore, you add $(+14˚F)$ to $(-17˚F)$ to determine the temperature at noon.