Answer
See below
Work Step by Step
Assume that $Av=\lambda v\\
Bv=\alpha v$
a) Take $(AB)v=A(\alpha v)=\alpha (Av)=\alpha \lambda v=(\lambda \alpha) v$
Hence, $v$ is an eigenvalue of the matrix $AB$
b) Take $(A+B)v=A(v)+B(v)=\lambda v +\alpha v=(\alpha +\lambda) v$
Hence, $v$ is an eigenvalue of the matrix $A+B$