Answer
$\frac{28}{\sqrt 10}$
Work Step by Step
From exercise 21, we have:
$d(P,L)=\frac{|y_0-x_0m-b|}{\sqrt 1+m^2}$
Since $P(-8,0)$ and $y=3x-4$, hence:
$$d(P,L)=\frac{|0-(-8).3-(-4)}{\sqrt 1+3^2}=\frac{28}{\sqrt 10}$$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 5 - Inner Product Spaces - 5.2 Orthogonal Sets of Vectors and Orthogonal Projections - Problems - Page 360: 22
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