Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 5 - Inner Product Spaces - 5.1 Definition of an Inner Product Space - Problems - Page 351: 27

Answer

See below

Work Step by Step

Let $u=(u_1,u_2)\\ v=(v_1,v_2)\\ w=(w_1,w_2)$ 1. Property: $=v_1v_1-v_1v_2-v_2v_1+4v_2v_2\\ =v_1^2-2v_1v_2+4v_2^2\\ =v_1^2-2v_1v_2+v_2^2+3v_2^2\\ =(v_1-v_2)^2+3v_2^2 \geq 0$ If $v=0 \rightarrow =(0-0)^2+3.0=0$ If $v \ne 0 \rightarrow (v_1-v_2)^2+3v_2^2 \gt 0$ Hence, the property $=0 \leftrightarrow v=0$ does not hold. 2. Property $=v_1w_1-v_1w_2-v_2w_1+4v_2w_2\\ =w_1v_1-w_1v_2-w_2v_1+4w_2v_2\\ =$ 3. Property $=(kv_1)w_1-(kv_1)w_2-(kv_2)w_1+4(kv_2)w_2\\ =kv_1w_1-kv_1w_2-kv_2w_1+4kv_2w_2\\ =k(v_1w_1-v_1w_2-v_2w_1+4v_2w_2)\\ =k$ 4. Property $=(u_1+v_1)w_1-(u_1+v_1)w_2-(u_2+v_2)w_1+4(u_2+v_2)w_2\\ =u_1w_1+v_1w_1-u_1w_2-v_1w_2-u_2w_1-v_2w_1+4u_2w_2+4v_2w_2\\ =(u_1w_1-u_1w_2-u_2w_1+4u_2w_2)+(v_1w_1-v_1w_2-v_2w_1+4v_2w_2)\\ =+$
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