Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 5 - Inner Product Spaces - 5.1 Definition of an Inner Product Space - Problems - Page 351: 20

Answer

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Work Step by Step

We are given: $v=(2,-1)\\ w=(3,6)$ a) Using the inner product (5.1.14) in Problem 18, we have: $=2.2.3+2.6+(-1)3+2.(-1).6=9$ b) Using the standard inner product in $R^2$: $=2.3+(-1).6=6-6=0$
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