Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 3 - Determinants - 3.5 Chapter Review - Additional Problems - Page 243: 6

Answer

24

Work Step by Step

(a) $|A|=\begin{vmatrix} 3 & -1 & -2 & 1\\ 0 & 0 &1& 4\\ 0 & 2 & 1 & -1\\ 0 &0 & 0 & -4 \end{vmatrix}=-3.1.2.(-4)=24$ b) Using elementary row operations: $|A|=\begin{vmatrix} 3 & -1 & -2 & 1\\ 0 & 0 &1& 4\\ 0 & 2 & 1 & -1\\ 0 &0 & 0 & -4 \end{vmatrix} \approx \begin{vmatrix} 3 & -1 & -2 & 1\\ 0 & 2 & 1 & -1 \\ 0 & 0 &1& 4\\ 0 &0 & 0 & -4 \end{vmatrix} =-3.2.1.(-4)=24$ c) Using the Cofactor Expansion Theorem $|A|=3\begin{vmatrix} 0 &1& 4\\ 2 & 1 & -1 \\ 0 &0 & -4 \end{vmatrix}=3.8=24$
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