Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 3 - Determinants - 3.5 Chapter Review - Additional Problems - Page 243: 3

Answer

24

Work Step by Step

(a) $|A|=\begin{vmatrix} 2 & 3 & -5\\ -4 & 0 & 2\\ 6 & -3 & 3 \end{vmatrix}=2.0.3+(-4)(-3)(-5)+6.3.2-(-5).0.6=24$ b) Using elementary row operations: $|A|=\begin{vmatrix} 2 & 3 & -5\\ -4 & 0 & 2\\ 6 & -3 & 3 \end{vmatrix} \approx \begin{vmatrix} 2 & 3 & -5\\ 0 & 6 & -8\\ 0 & -12 & 18 \end{vmatrix} \approx \begin{vmatrix} 2 & 3 & -5\\ 0 & 6 & -8\\ 0 & 0 & 2 \end{vmatrix}=24$ c) Using the Cofactor Expansion Theorem $|A|=A_{13}C_{13}+A_{23}C_{23}=-3.(-24)+3.(-16)=24$
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