Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 3 - Determinants - 3.2 Properties of Determinants - Problems - Page 219: 15

Answer

non-invertible.

Work Step by Step

We know that the determinant of a matrix \[ \left[\begin{array}{rr} a & b \\ c &d \\ \end{array} \right] \] is $D=ad-bc$. Also, a matrix is non-invertible if and only if $D=0$. Hence here $D=(-1)(-1)-1\cdot1=1-1=0$, thus it is non-invertible.
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