Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 3 - Determinants - 3.1 The Definition of the Determinant - Problems - Page 207: 45

Answer

See below

Work Step by Step

Given $$ A=\begin{bmatrix} e^{2t} & e^{3t} & e^{-4t} \\ 2e^{2t} & 3e^{3t} & -4e^{-4t} \\ 4e^{2t} & 9e^{3t} & 16e^{-4t} \end{bmatrix}$$ So, we get $det (A)=\begin{vmatrix} e^{2t} & e^{3t} & e^{-4t} \\ 2e^{2t} & 3e^{3t} & -4e^{-4t} \\ 4e^{2t} & 9e^{3t} & 16e^{-4t} \end{vmatrix}\\ =e^{2t}.3e^{3t}.16e^{-4t}+e^{3t}.(-4e^{-4t}).(4e^{2t})+e^{-4t}2e^{2t}.9e^{3t}-e^{-4t}.3e^{3t}.4e^{2t}-e^{2t}.(-4e^{-4t}).9e^{3t}-e^{3t}.2e^{2t}.16e^{-4t}\\ =48e^t-16e^t+18e^t-12e^t+36e^t-32e^t\\ =42e^t$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.