Answer
See answers below
Work Step by Step
A is an $n \times n$ invertible symmetric matrix.
Since A is symmetric, we will have $A^T=A$ and $(A^T)^{-1}=A^{-1}$
According to Theorem 2.6.10, $(A^T)^{-1}=(A^{-1})^T$
Hence here, $(A^{-1})^T=A^{-1}$ and $A^{-1}$ is symmetric