Answer
$1$
Work Step by Step
The radius of convergence of a power series represented by $\dfrac{A(x)}{B(x)}$ can be defined as the distance from $min(|x_0-y|)$, where y is root of $B(x)$, that is, $B(y)=0$.
We have: $\dfrac{A(x)}{B(x)}=\dfrac{x}{x^2+1}; x_0=0$
This implies that the root of $B(x)=x^2+1=0 \implies x =\pm i$
So, the radius of convergence is $R=|0 \pm i|=1$