Answer
See below
Work Step by Step
Shift $n \rightarrow m+2$:
$\sum n(n-1)a_{n-1}x^{n-2}=\sum (m+1)(m+2)a_{m+1}x^m$
Shift $n \rightarrow m+1$:
$\sum na_{n}x^{n-1}=\sum (m+1)a_{m+1}x^m$
Hence, $\sum n(n-1)a_{n-1}x^{n-2}+\sum na_{n}x^{n-1}=\sum (m+1)(m+2)a_{m+1}x^m +\sum (m+1)a_{m+1}x^m\\
=\sum (m+1)(m+1+2)a_{m+1}x^m\
=\sum (m+1)(m+3)a_{m+1}x^m$