Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 11 - Series Solutions to Linear Differential Equations - 11.1 A Review of Power Series - Problems - Page 730: 13

Answer

See below

Work Step by Step

Shift $n \rightarrow m+2$: $\sum n(n-1)a_{n-1}x^{n-2}=\sum (m+1)(m+2)a_{m+1}x^m$ Shift $n \rightarrow m+1$: $\sum na_{n}x^{n-1}=\sum (m+1)a_{m+1}x^m$ Hence, $\sum n(n-1)a_{n-1}x^{n-2}+\sum na_{n}x^{n-1}=\sum (m+1)(m+2)a_{m+1}x^m +\sum (m+1)a_{m+1}x^m\\ =\sum (m+1)(m+1+2)a_{m+1}x^m\ =\sum (m+1)(m+3)a_{m+1}x^m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.