Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 11 - Series Solutions to Linear Differential Equations - 11.1 A Review of Power Series - Problems - Page 730: 4

Answer

$\dfrac{1}{2}$

Work Step by Step

We need to apply ratio test for a given series. $\lim\limits_{n \to \infty} |\dfrac{a_{n+1}}{a_n}|=\lim\limits_{n \to \infty} |\dfrac{2^{n+1}}{n+1} \times \dfrac{n}{2^n}|=2$ This implies that the radius of convergence of the series is $\dfrac{1}{2}$ and the series converges at $[-\dfrac{1}{2},\dfrac{1}{2})$ but diverges at endpoint $\dfrac{1}{2}$.
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