Answer
$\dfrac{2}{(s-1)^3} -\dfrac{6}{s^3}$
Work Step by Step
The Laplace transform of function are is given as:
$L(t^2)=\dfrac{2}{s^3}$ and $L(3t^2)=\dfrac{6}{s^3}$
The first shifting Theorem for $a= 2$ can be expressed as:
$L[t^2e^{t}-3t^2]=\dfrac{2}{(s-1)^3} -\dfrac{6}{s^3}$
