Answer
$\dfrac{e^{-2t}}{e^2}$
Work Step by Step
The first shifting Theorem can be expressed as:
When $L[f]=F(s)$, then we have: $L[e^{at}f(t)]=F(s-a)$
Now, $f(t-a) =f(t+1) \\=e^{-2(t+1)} \\=e^{-2t-2}\\=\dfrac{e^{-2t}}{e^2}$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 10 - The Laplace Transform and Some Elementary Applications - 10.5 The First Shifting Theorem - Problems - Page 694: 2
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