Answer
$L[ t e^{2t}]=\dfrac{1}{(s-2)^2}$
Work Step by Step
The Laplace transform of function $t$ is given as:
$L(t)=\dfrac{1}{s^2}$
The first shifting Theorem for $a=2$ can be expressed as:
$L[ t e^{2t}]=\dfrac{1}{(s-2)^2}$
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