College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.9 - Modeling with Equations - P.9 Exercises - Page 73: 66

Answer

35 yd.

Work Step by Step

The length of the two semicircular parts form a circle and the circumference of this circle is equal to $440 - 110 - 110 = 220 yd.$ The circumference of a circle is equal to $2\pi r$. Using this formula, substitute 220 yd in and find r. $2\pi r = 220$ $r = 220 \div (2\pi)$ $r \approx 35$. Therefore, the radius of the semicircular parts is 35 yd.
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