College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.9 - Modeling with Equations - P.9 Exercises - Page 73: 64

Answer

1200lb.

Work Step by Step

Using the law $w_{1}x_{1} = w_{2}x_{2}$, plug 25 ft, 240lb, and 5ft into $w_{1}, x_{1},$ and $ w_{2}$ respectively. We obtain $6000 = 5x_{2}$. Therefore, $x_{2}$ = $6000 \div 5 = 1200$lb.
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