Answer
The woman needs to travel at $54.99$ m/hr to pass the truck in $6$ seconds.
Work Step by Step
-The back of the women's car is at $-14ft$ of the back of a truck. and after passing the front of the truck, the back of the women's car is at $0ft$ in front of the truck's front. Therefore, the woman needs to travel $14ft+$length of the truck to pass the truck. $14ft+30ft=44ft$.To pass the truck in $6$ seconds, $44ft\div6sec=7.33 ft/sec$. So the woman needs to travel $7.33ft/sec$ more than the truck's speed of $50m/hr$ to pass the truck in $6$ seconds.
$\frac{1ft/sec}{7.33ft/sec}=\frac{0.681818m/hr}{x}$
$x=4.999m/hr$.
Therefore, The woman needs to travel at $54.99m/hr$ to pass the truck in $6$ seconds.
