College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.9 - Modeling with Equations - P.9 Exercises - Page 72: 49

Answer

$18$g

Work Step by Step

Currently there is $18\cdot5\cdot0.1=9$g of silver. So if she adds $x$ grams, the equation becomes: $\frac{9+x}{90+x}=0.25\\9+x=0.25(90+x)\\9+x=22.5+0.25x\\0.75x=13.5\\x=18$
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