College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Section 9.1 - Counting - 9.1 Exercises - Page 658: 56

Answer

39916800

Work Step by Step

We can order the letters, if they were distinguishable in $12!$ ways. However, we can switch around the E's and Y's so we can order the E's in 6 ways and the Y's in 2 ways. $12!/12 = 11! = 39916800$
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