College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Section 9.1 - Counting - 9.1 Exercises - Page 658: 54

Answer

$72072$ ways

Work Step by Step

There are $14$ total balls, and there are three groups of indistinguishable colors (the groups have 5, 2, and 7 balls). Therefore, the amount of ways the balls can be arranged is $\frac{14!}{5!\times 2!\times 7!}=72072$ ways.
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