College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Chapter 9 Test - Page 686: 13

Answer

$\frac{41}{96}$, or $\approx 0.427$

Work Step by Step

The probability of at least 2 people having the same astrological sign is the same as 1 minus the probability of no one having the same astrological sign (everyone having a different sign). The probability of no one having the same sign is $ 1 \times \frac{11}{12} \times \frac{10}{12} \times \frac{9}{12} = \frac{55}{96}$, so the probability of at least 2 people having the same sign is $1 - \frac{55}{96} = \frac{41}{96}$.
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