Answer
a) $\frac{5}{13}$
b) $\frac{6}{13}$
c) $\frac{9}{13}$
Work Step by Step
a) There are 5 red balls and 13 balls in total, so the probability of drawing a red ball is $\frac{5}{13}$.
b) There are 2 even-numbered red balls and 4 even-numbered white balls, so there are 6 even-numbered balls and 13 in total, so the probability of drawing an even-numbered ball is $\frac{6}{13}$.
c) There are 5 red balls and 4 even-numbered white balls, so there are 9 red or even-numbered balls, so the probability of drawing a red or even-numbered ball is $\frac{9}{13}$.