College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Chapter 9 Review - Exercises - Page 684: 22

Answer

34650

Work Step by Step

There are 11 letters in this word, and 4 I's, 4 Ss, and 2 Ps are repeated. Therefore, the number of anagrams is $ \frac{11!}{4!4!2!} = 34650$.
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