College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Chapter 9 Review - Exercises - Page 684: 20

Answer

12

Work Step by Step

There are 4 letters in this word, and 2 repeated letters, so there are $4!\div 2! = 12$ anagrams.
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