College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 7, Conic Sections - Chapter 7 Review - Exercises - Page 584: 40

Answer

$$\frac{-1}{4}*(y-4)^2 = x-4$$

Work Step by Step

The graph is going to be of the form $$a(y-4)^2 = x-4$$ Since there is a vertex at $(4,4)$. Also, the graph passes through the origin. We plug that in... $$a(0-4)^2 = 0-4$$ $$16a = -4$$ $$a = -1/4$$ Thus the answer is, $$-1/4(y-4)^2 = x-4$$
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