## College Algebra 7th Edition

$$\frac{y^2}{4^2} - \frac{x^2}{3^2}=1$$
The center of the graph is at $(0,0)$ and the graph is oriented vertically. $$\frac{y^2}{a^2} - \frac{x^2}{b^2}=1$$ Thus, $a = 4$ as that is the y-intercept. Also, by the theorem $a^2+b^2=c^2$ $b = 3$ $$\frac{y^2}{4^2} - \frac{x^2}{3^2}=1$$