College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 7, Conic Sections - Chapter 7 Review - Exercises - Page 584: 39


$$\frac{y^2}{4^2} - \frac{x^2}{3^2}=1$$

Work Step by Step

The center of the graph is at $(0,0)$ and the graph is oriented vertically. $$\frac{y^2}{a^2} - \frac{x^2}{b^2}=1$$ Thus, $a = 4$ as that is the y-intercept. Also, by the theorem $a^2+b^2=c^2$ $b = 3$ $$\frac{y^2}{4^2} - \frac{x^2}{3^2}=1$$
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