College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 6, Matrices and Determinants - Section 6.1 - Matrices and Systems of Linear Equations - 6.1 Exercises - Page 501: 27

Answer

$a.$ $\left\{ \begin{aligned} x+2y+3z-w&=7\\ y-z&=5\\ z+2w&=5\\ w&=3\end{aligned}\right.$ $b.$ $(7,3,-1,3)$

Work Step by Step

$a.$ $\left\{ \begin{aligned} x+2y+3z-w&=7\\ y-z&=5\\ z+2w&=5\\ w&=3\end{aligned}\right.$ $b.$ The 4th equation gives $w=3$. Back-substituting $w=3$ into the 3rd equation, $z+2(3)=5\quad \Rightarrow\quad z=-1.$ Back-substituting $w=3$ and $z=-1$ into the 2nd equation, $y-2(-1)=5\quad \Rightarrow\quad y=3.$ Back-substituting into the 1st equation, $x+2(3)+3(-1)-(3)=7\quad \Rightarrow\quad x=7.$ The solution is $(7,3,-1,3)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.