## College Algebra 7th Edition

$f^{-1}(x)= \frac{10^{x}}{3}$
We are given: $f(x)=\log 3x$ To find the inverse, we switch $x$ and $y$ and solve for $y$: $y= \log 3x$ $x= \log 3y$ $10^{x}=3y$ $y=\frac{10^{x}}{3}$ Therefore: $f^{-1}(x)= \frac{10^{x}}{3}$