Answer
(a). $T=200e^{-0.11t}+20$
(b). $T=42.161$
Work Step by Step
$\ln \left(\frac{T-20}{200} \right)=-0.11t$
(a).
$\frac{T-20}{200} = e^{-0.11t},$
$T-20=200e^{-0.11t},$
$T=200e^{-0.11t}+20$
(b).
$t=20$
$T=200e^{-2.2}+20,$
$T=42.161$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 405: 100
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