College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.4 - Laws of Logarithms - 4.4 Exercises - Page 394: 7

Answer

(a) False (b) True

Work Step by Step

(a) This is false. $\log(A+B)\neq\log A+\log B$ We can show this thus: $\log A+\log B=log(AB)\neq log(A+B)$ (since $A+B\neq AB$) (b) This is true. $\log AB=\log A+\log B$ (This is a general property of logs.)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.