#### Answer

sum
$\log_{5}(25\cdot 125)=\log_{5}25+\log_{5}125=2+3=5$

#### Work Step by Step

The logarithm of a product of two numbers is the same as the ___sum___ of the logarithms of these numbers. So ___$\log_{5}(25\cdot 125)=\log_{5}25+\log_{5}125=2+3=5$___.