College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.4 - Laws of Logarithms - 4.4 Exercises - Page 394: 1

Answer

sum $\log_{5}(25\cdot 125)=\log_{5}25+\log_{5}125=2+3=5$

Work Step by Step

The logarithm of a product of two numbers is the same as the ___sum___ of the logarithms of these numbers. So ___$\log_{5}(25\cdot 125)=\log_{5}25+\log_{5}125=2+3=5$___.
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