College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 389: 99

Answer

$11.55,9.9,8.67$ years

Work Step by Step

Plugging in $r=0.06,0.07,0.08$ into the formula, we get (respectively): $t=\frac{\ln(2)}{0.06}\approx11.55$, $t=\frac{\ln(2)}{0.07}\approx9.9$, $t=\frac{\ln(2)}{0.08}\approx8.67$
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