College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 389: 96

Answer

$891.69$

Work Step by Step

Plugging in $I=0.7I_0$ into the formula, we get: $C=-2500\ln(\frac{0.7I_0}{I_0})=-2500\ln(0.7)\approx891.69$
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