#### Answer

(a) $\log_6{36}=2$
(b) $\log{(\frac{1}{10})}=-1$

#### Work Step by Step

RECALL:
$b^y=x \longrightarrow \log_b{x}=y$
Use the rule above to obtain:
(a) $\log_6{36}=2$
(b) $\log{(\frac{1}{10})}=-1$ (note that common logarithm has $b=10$)